JEE MAIN - Physics (2022 - 28th June Evening Shift - No. 9)
What will be the effect on the root mean square velocity of oxygen molecules if the temperature is doubled and oxygen molecule dissociates into atomic oxygen?
The velocity of atomic oxygen remains same
The velocity of atomic oxygen doubles
The velocity of atomic oxygen becomes half
The velocity of atomic oxygen becomes four times
Explanation
As $${v_{rms}} = \sqrt {{{3RT} \over {{M_0}}}} $$
T is doubled and oxygen molecule is dissociated into atomic oxygen molar mass is halved.
So, $$v{'_{rms}} = \sqrt {{{3RT \times 2{T_0}} \over {{M_0}/2}}} = 2{v_{rms}}$$
So velocity of atomic oxygen is doubled.
Comments (0)
