JEE MAIN - Physics (2022 - 28th June Evening Shift - No. 11)
Resistance of the wire is measured as 2 $$\Omega$$ and 3 $$\Omega$$ at 10$$^\circ$$C and 30$$^\circ$$C respectively. Temperature co-efficient of resistance of the material of the wire is :
0.033 $$^\circ$$C$$-$$1
$$-$$0.033 $$^\circ$$C$$-$$1
0.011 $$^\circ$$C$$-$$1
0.055 $$^\circ$$C$$-$$1
Explanation
R10 = 2 = R0(1 + $$\alpha$$ $$\times$$ 10)
R30 = 3 = R0(1 + $$\alpha$$ $$\times$$ 30)
On solving
$$\alpha$$ = 0.033/$$^\circ$$C
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