JEE MAIN - Physics (2022 - 28th June Evening Shift - No. 10)

Two point charges A and B of magnitude +8 $$\times$$ 10^$$-$$6 C and $$-$$8 $$\times$$ 10^$$-$$6 C respectively are placed at a distance d apart. The electric field at the middle point O between the charges is 6.4 $$\times$$ 10⁴ NC^$$-$$1. The distance 'd' between the point charges A and B is :

2.0 m

3.0 m

1.0 m

4.0 m

Explanation

JEE Main 2022 (Online) 28th June Evening Shift Physics - Electrostatics Question 109 English Explanation

Electric field at P will be

$$E = {{kq} \over {{{(d/2)}^2}}} \times 2 = {{8kq} \over {{d^2}}}$$

So, $${{8 \times 9 \times {{10}^9} \times 8 \times {{10}^{ - 6}}} \over {{d^2}}} = 6.4 \times {10^4}$$

So, $$d = 3$$ m

JEE MAIN - Physics (2022 - 28th June Evening Shift - No. 10)

Explanation

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