JEE MAIN - Physics (2022 - 28th July Morning Shift - No. 5)
If the radius of earth shrinks by $$2 \%$$ while its mass remains same. The acceleration due to gravity on the earth's surface will approximately :
decrease by $$2 \%$$
decrease by $$4 \%$$
increase by $$2 \%$$
increase by $$4 \%$$
Explanation
The acceleration due to gravity (g) on the surface of a planet is given by the formula:
$$g = \frac{G M}{R^2}$$
where:
- G is the gravitational constant,
- M is the mass of the planet,
- R is the radius of the planet.
If the radius of the Earth shrinks by 2% but its mass remains the same, the new acceleration due to gravity (g') will be:
$$g' = \frac{G M}{(0.98R)^2} = \frac{G M}{0.9604 R^2} = \frac{g}{0.9604}$$
This implies that g' is approximately 1.0412 times g, or an increase of approximately 4.12%.
Therefore, the acceleration due to gravity on the Earth's surface will approximately increase by 4%.
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