JEE MAIN - Physics (2022 - 28th July Morning Shift - No. 4)
A balloon has mass of $$10 \mathrm{~g}$$ in air. The air escapes from the balloon at a uniform rate with velocity $$4.5 \mathrm{~cm} / \mathrm{s}$$. If the balloon shrinks in $$5 \mathrm{~s}$$ completely. Then, the average force acting on that balloon will be (in dyne).
3
9
12
18
Explanation
$${F_{avg}} = \mu \times {v_{rel}}$$
$$ = {{10} \over 5} \times 4.5 = 9$$
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