JEE MAIN - Physics (2022 - 28th July Evening Shift - No. 11)
Given below are two statements :
Statement I : A uniform wire of resistance $$80 \,\Omega$$ is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be $$5 \,\Omega$$.
Statement II: Two resistances 2R and 3R are connected in parallel in a electric circuit. The value of thermal energy developed in 3R and 2R will be in the ratio $$3: 2$$.
In the light of the above statements, choose the most appropriate answer from the option given below
Both statement I and statement II are correct
Both statement I and statement II are incorrect
Statement I is correct but statement II is incorrect
Statement I is incorrect but statement II is correct
Explanation
Statement I : $${R_{1\,part}} = {{80} \over 4} = 20\,\Omega $$
$$ \Rightarrow {R_{eff}} = {{20} \over 4} = 5\,\Omega $$
Statement II : Ratio $$ = {{{{{{(\Delta V)}^2}} \over {3R}}} \over {{{{{(\Delta V)}^2}} \over {2R}}}}$$
$$ = {2 \over 3}$$
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