JEE MAIN - Physics (2022 - 27th June Morning Shift - No. 6)
A 72 $$\Omega$$ galvanometer is shunted by a resistance of 8 $$\Omega$$. The percentage of the total current which passes through the galvanometer is :
0.1%
10%
25%
0.25%
Explanation
_27th_June_Morning_Shift_en_6_1.png)
From the given setup
$$y \times {R_G} = (x - y)({R_S})$$
$$ \Rightarrow y \times 72 = (x - y) \times 8$$
$$ \Rightarrow 9y = x - y$$
$$ \Rightarrow y = {x \over {10}}$$ or 10% of x
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