JEE MAIN - Physics (2022 - 27th June Evening Shift - No. 7)

For a perfect gas, two pressures P₁ and P₂ are shown in figure. The graph shows :

JEE Main 2022 (Online) 27th June Evening Shift Physics - Heat and Thermodynamics Question 172 English

P₁ > P₂

P₁ < P₂

P₁ = P₂

Insufficient data to draw any conclusion

As per ideal gas equation, $$V = {{nR} \over P}T$$

$$\Rightarrow$$ Slope of V-T graph is inversely proportional to P.

As m₂ > m₁ $$\Rightarrow$$ P₁ > P₂