JEE MAIN - Physics (2022 - 27th June Evening Shift - No. 22)
A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ___________ s.
Answer
1
Explanation
A = 8 cm
T = 6 s
$$A\cos \left( {{{2\pi t} \over T}} \right) = {A \over 2}$$
$$ \Rightarrow {{2\pi t} \over T} = {\pi \over 3}$$
or $$t = {T \over 6} = 1\,s$$
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