JEE MAIN - Physics (2022 - 27th June Evening Shift - No. 11)
If a charge q is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be :
_27th_June_Evening_Shift_en_11_1.png)
$${q \over {{ \in _0}}}$$
$${q \over {{ 2\in _0}}}$$
$${q \over {{ 4\in _0}}}$$
$${q \over {{ 2\pi\in _0}}}$$
Explanation
Flux passing through flat surface = Flux passing through curved surface.
So, $$\phi = {q \over {2{\varepsilon _0}}}$$
Comments (0)
