JEE MAIN - Physics (2022 - 27th July Morning Shift - No. 6)
Two satellites $$\mathrm{A}$$ and $$\mathrm{B}$$, having masses in the ratio $$4: 3$$, are revolving in circular orbits of radii $$3 \mathrm{r}$$ and $$4 \mathrm{r}$$ respectively around the earth. The ratio of total mechanical energy of $$\mathrm{A}$$ to $$\mathrm{B}$$ is :
9 : 16
16 : 9
1 : 1
4 : 3
Explanation
$$U = - {{G{M_e}m} \over {2r}}$$
So, $${{{U_A}} \over {{U_B}}} = {{{m_A}} \over {{m_B}}} \times {{{r_B}} \over {{r_A}}}$$
$$ = {4 \over 3} \times {4 \over 3} = {{16} \over 9}$$
Comments (0)
