JEE MAIN - Physics (2022 - 27th July Morning Shift - No. 22)
A long cylindrical volume contains a uniformly distributed charge of density $$\rho \,\mathrm{Cm}^{-3}$$. The electric field inside the cylindrical volume at a distance $$x=\frac{2 \varepsilon_{0}}{\rho} \mathrm{m}$$ from its axis is ________ $$\mathrm{Vm}^{-1}$$.
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Answer
1
Explanation
$$E = {{\rho r} \over {2{\varepsilon _0}}}$$
at $$r = {{2{\varepsilon _0}} \over \rho }$$
$$E = {\rho \over {2{\varepsilon _0}}}\left( {{{2{\varepsilon _0}} \over \rho }} \right)$$
$$ = 1$$
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