JEE MAIN - Physics (2022 - 27th July Evening Shift - No. 23)
A spherical soap bubble of radius 3 cm is formed inside another spherical soap bubble of radius 6 cm. If the internal pressure of the smaller bubble of radius 3 cm in the above system is equal to the internal pressure of the another single soap bubble of radius r cm. The value of r is ___________.
Answer
2
Explanation
$${{4T} \over {{R_1}}} + {{4T} \over {{R_2}}} = {{4T} \over r}$$
$$ \Rightarrow {1 \over r} = {1 \over 3} + {1 \over 6} \Rightarrow r = 2$$ cm
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