JEE MAIN - Physics (2022 - 27th July Evening Shift - No. 18)
A thin prism of angle $$6^{\circ}$$ and refractive index for yellow light $$\left(\mathrm{n}_{\mathrm{Y}}\right) 1.5$$ is combined with another prism of angle $$5^{\circ}$$ and $$\mathrm{n}_{\mathrm{Y}}=1.55$$. The combination produces no dispersion. The net average deviation $$(\delta)$$ produced by the combination is $$\left(\frac{1}{x}\right)^{\circ}$$. The value of $$x$$ is ____________.
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Answer
4
Explanation
$${\delta _{net}} = {\delta _1} + {\delta _2}$$
$$ = |({\mu _1} - 1){A_1} - ({\mu _2} - 1){A_2}|$$
$$ = |3^\circ - 2.75^\circ |$$
$${\delta _{net}} = {{1^\circ } \over 4}$$
$$ \Rightarrow x = 4$$
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