JEE MAIN - Physics (2022 - 26th June Morning Shift - No. 19)
A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ________ m. [Use g = 10 m/s2]
Answer
5
Explanation
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Let at h height its velocity becomes 10 m/s (as given in question)
$$ \Rightarrow {v^2} - {u^2} = 2( - 10) \times ( - h)$$
$$ \Rightarrow {v^2} = 20\,h$$
$$ \Rightarrow 100 = 20\,h$$
$$ \Rightarrow h = 5\,m$$
$$h' = 10 - 5 = 5\,m$$
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