JEE MAIN - Physics (2022 - 26th June Morning Shift - No. 15)
In free space, an electromagnetic wave of 3 GHz frequency strikes over the edge of an object of size $${\lambda \over {100}}$$, where $$\lambda$$ is the wavelength of the wave in free space. The phenomenon, which happens there will be :
Reflection
Refraction
Diffraction
Scattering
Explanation
$$
\frac{\mathrm{a}}{\lambda}=\frac{1}{100}
$$
For reflection size of obstacle must be much larger than wavelength, for diffraction size should be order of wavelength.
Since the object is of size $\frac{\lambda}{100}$, much smaller than wavelength, so scattering will occur.
For reflection size of obstacle must be much larger than wavelength, for diffraction size should be order of wavelength.
Since the object is of size $\frac{\lambda}{100}$, much smaller than wavelength, so scattering will occur.
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