JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 9)
A parallel plate capacitor with plate area A and plate separation d = 2 m has a capacitance of 4 $$\mu$$F. The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K = 3 (as shown in figure) will be :
_26th_June_Evening_Shift_en_9_1.png)
2$$\mu$$F
32$$\mu$$F
6$$\mu$$F
8$$\mu$$F
Explanation
Equivalent circuit is
_26th_June_Evening_Shift_en_9_2.png)
Now, $${{{\varepsilon _0}A} \over d} = 4\,\mu F$$
$$ \Rightarrow {{12} \over 8}{{{\varepsilon _0}A} \over d} = 6\,\mu F$$
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