JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 7)
A flask contains argon and oxygen in the ratio of 3 : 2 in mass and the mixture is kept at 27$$^\circ$$C. The ratio of their average kinetic energy per molecule respectively will be :
3 : 2
9 : 4
2 : 3
1 : 1
Explanation
$$K{E_{avg}} = {3 \over 2}kT$$ (At lower temperature)
As temperature is same for both the gases.
$$\Rightarrow$$ Both gases will have same average kinetic energy.
$$ \Rightarrow {{{{(K{E_{avg}})}_{\arg on}}} \over {{{(K{E_{avg}})}_{oxygen}}}} = {1 \over 1}$$
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