JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 23)
Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10$$-$$5 N, then separation between the wires is ____________ cm.
Answer
5
Explanation
$${{dF} \over {dl}} = {{{\mu _0}{i_1}{i_2}} \over {2\pi d}}$$
So $${{2 \times {{10}^{ - 7}} \times 5 \times 5} \over d} = {{{{10}^{ - 5}}} \over {10 \times {{10}^{ - 2}}}}$$
$$d = {{2 \times {{10}^{ - 7}} \times 5 \times 5} \over {{{10}^{ - 4}}}}$$
= 50 mm
= 5 cm
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