JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 2)
In the arrangement shown in figure a1, a2, a3 and a4 are the accelerations of masses m1, m2, m3 and m4 respectively. Which of the following relation is true for this arrangement?
4a1 + 2a2 + a3 + a4 = 0
a1 + 4a2 + 3a3 + a4 = 0
a1 + 4a2 + 3a3 + 2a4 = 0
2a1 + 2a2 + 3a3 + a4 = 0
Explanation
From virtual work done method,
4T $$\times$$ a1 + 2T $$\times$$ a2 + T $$\times$$ a3 + T $$\times$$ a4 = 0
$$\Rightarrow$$ 4a1 + 2a2 + a3 + a4 = 0
Comments (0)
