JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 14)
A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s$$-$$1. If the horizontal component of earth's magnetic field is 0.2 $$\times$$ 10$$-$$4 T, then emf induced between the two ends of the conductor is :
5 $$\mu$$V
50 $$\mu$$V
5 mV
50 mv
Explanation
$$Emf = {1 \over 2}B\omega {l^2}$$
$$ = {1 \over 2} \times 0.2 \times {10^{ - 4}} \times 5 \times {1^2}$$ V
= 0.5 $$\times$$ 10$$-$$4 V
= 50 $$\mu$$V
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