JEE MAIN - Physics (2022 - 26th June Evening Shift - No. 1)
The dimension of mutual inductance is :
$$[M{L^2}{T^{ - 2}}{A^{ - 1}}]$$
$$[M{L^2}{T^{ - 3}}{A^{ - 1}}]$$
$$[M{L^2}{T^{ - 2}}{A^{ - 2}}]$$
$$[M{L^2}{T^{ - 3}}{A^{ - 2}}]$$
Explanation
$$\because$$ $$U = {1 \over 2}M{i^2}$$
$$ \Rightarrow [M] = {{[U]} \over {[{i^2}]}} = {{M{L^2}{T^{ - 2}}} \over {{A^2}}}$$
$$ = [M{L^2}{T^{ - 2}}{A^{ - 2}}]$$
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