JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 8)

The current I in the given circuit will be :

JEE Main 2022 (Online) 26th July Morning Shift Physics - Current Electricity Question 125 English

10 A

20 A

4 A

40 A

JEE Main 2022 (Online) 26th July Morning Shift Physics - Current Electricity Question 125 English Explanation

The grouping of resistance is a wheatstone bridge

So, $${R_{net}} = 4\,\Omega $$

So, $$i = {V \over {{R_{net}}}} = 10\,A$$