JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 27)

In the circuit shown below, maximum zener diode current will be _________ $$\mathrm{mA}$$.

JEE Main 2022 (Online) 26th July Morning Shift Physics - Semiconductor Question 65 English

Answer

JEE Main 2022 (Online) 26th July Morning Shift Physics - Semiconductor Question 65 English Explanation

$${i_s} = {{60} \over {4 \times {{10}^3}}} = 15 \times {10^{ - 3}} = 15$$ mA

$${i_L} = {{60} \over {10 \times {{10}^3}}} = 6$$ mA

$${I_z} = {i_s} - {i_L} = 9$$ mA