JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 11)

7 mol of a certain monoatomic ideal gas undergoes a temperature increase of $$40 \mathrm{~K}$$ at constant pressure. The increase in the internal energy of the gas in this process is :

(Given $$\mathrm{R}=8.3 \,\mathrm{JK}^{-1} \mathrm{~mol}^{-1}$$ )

5810 J
3486 J
11620 J
6972 J

Explanation

$$\Delta U = n{C_v}\Delta T$$

$$ = 7 \times {{3R} \over 2} \times 40$$

$$ = 3486\,J$$

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