JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 10)
When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :
Circular
Elliptical
Sinusoidal
Straight line
Explanation
Let $$x = A\sin \omega t$$
$$ \Rightarrow v = A\omega \cos \omega t$$
$$ \Rightarrow v = \, \pm \,\omega \sqrt {{A^2} - {x^2}} $$
$$ \Rightarrow {{{v^2}} \over {{\omega ^2}}} + {x^2} = {A^2}$$
$$\Rightarrow$$ Ellipse
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