JEE MAIN - Physics (2022 - 26th July Evening Shift - No. 4)

A body of mass $$8 \mathrm{~kg}$$ and another of mass $$2 \mathrm{~kg}$$ are moving with equal kinetic energy. The ratio of their respective momentum will be :
1 : 1
2 : 1
1 : 4
4 : 1

Explanation

$$P = \sqrt {2m\,KE} $$

$$ \Rightarrow {{{P_1}} \over {{P_2}}} = \sqrt {{{{m_1}} \over {{m_2}}}} $$

$$ = \sqrt {{8 \over 2}} = {2 \over 1}$$

Comments (0)

Advertisement