JEE MAIN - Physics (2022 - 26th July Evening Shift - No. 20)
The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be ___________ $$\mathrm{m}$$.
Given, the length of the rod is $$10 \sqrt{3} \mathrm{~m}$$.
Answer
5
Explanation
$$l = {{M{L^2}} \over {12}} = M{K^2}$$
$$K = {L \over {\sqrt {12} }} = {{10\sqrt 3 } \over {\sqrt {12} }} = 5\,m$$
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