JEE MAIN - Physics (2022 - 26th July Evening Shift - No. 13)
A battery of $$6 \mathrm{~V}$$ is connected to the circuit as shown below. The current I drawn from the battery is :
1A
2A
$$\frac{6}{11}$$ A
$$\frac{4}{3}$$ A
Explanation
Balance wheatstone
$$ \Rightarrow {R_{eff}} = {{3 \times 6} \over {3 + 6}} \times 2 + 2$$
$$ = 6\,\Omega $$
$$ \Rightarrow I = {V \over R} = 1\,A$$
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