JEE MAIN - Physics (2022 - 25th June Morning Shift - No. 8)
In the figure, a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance l and 2l from the charge distribution. If $$\sigma$$ is the surface charge density, then the magnitude of electric fields E1 and E2 at P1 and P2 respectively are :
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$${E_1} = \sigma /{\varepsilon _0},\,{E_2} = \sigma /2{\varepsilon _0}$$
$${E_1} = 2\sigma /{\varepsilon _0},\,{E_2} = \sigma /{\varepsilon _0}$$
$${E_1} = {E_2} = \sigma /2{\varepsilon _0}$$
$${E_1} = {E_2} = \sigma /{\varepsilon _0}$$
Explanation
For an infinite charged plane
$$E = {\sigma \over {2{\varepsilon _0}}}$$ for any value of l
$$ \Rightarrow {E_1} = {E_2} = {\sigma \over {2{\varepsilon _0}}}$$
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