JEE MAIN - Physics (2022 - 25th June Morning Shift - No. 17)
The difference of speed of light in the two media A and B (vA $$-$$ vB) is 2.6 $$\times$$ 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 $$\times$$ 108 ms$$-$$1)
1.303
1.318
1.13
0.12
Explanation
Speed of light in a medium $$ = {c \over n}$$
$$\Rightarrow$$ According to given information,
$${c \over {{n_A}}} - {c \over {{n_B}}} = 2.6 \times {10^7}$$
$$ \Rightarrow {{{n_B}} \over {{n_A}}} - 1 = {{2.6 \times {{10}^7}} \over {3 \times {{10}^8}}} \times {n_B}$$
$$ \Rightarrow {{{n_B}} \over {{n_A}}} \simeq 1.13$$
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