JEE MAIN - Physics (2022 - 25th June Evening Shift - No. 9)
Two cells of same emf but different internal resistances r1 and r2 are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, is :
r2 $$-$$ r1
r1 $$-$$ r2
r1
r2
Explanation
$$I = {{2\varepsilon } \over {R + {r_1} + {r_2}}}$$
As per the question,
$${{2\varepsilon } \over {R + {r_1} + {r_2}}} \times {r_2} - \varepsilon = 0$$
$$ \Rightarrow R = {r_2} - {r_1}$$
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