JEE MAIN - Physics (2022 - 25th June Evening Shift - No. 6)
The ratio of specific heats $$\left( {{{{C_P}} \over {{C_V}}}} \right)$$ in terms of degree of freedom (f) is given by :
$$\left( {1 + {f \over 3}} \right)$$
$$\left( {1 + {2 \over f}} \right)$$
$$\left( {1 + {f \over 2}} \right)$$
$$\left( {1 + {1 \over f}} \right)$$
Explanation
$${{{C_P}} \over {{C_V}}} = \gamma $$
$${C_V} = \left( {{f \over 2}} \right)R$$ and $${C_P} - {C_V} = R$$
$$ \Rightarrow {{{C_P}} \over C} = {{1 + f/2} \over {f/2}} = 1 + {2 \over f}$$
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