JEE MAIN - Physics (2022 - 25th June Evening Shift - No. 25)
27 identical drops are charged at 22V each. They combine to form a bigger drop. The potential of the bigger drop will be _____________ V.
Answer
198
Explanation
Let the charge on one drop is q and its radius is r.
So for one drop $$V = {{kq} \over r}$$
For 27 drops merged new charge will be Q = 27 q and new radius is R = 3r
So new potential is
$$V' = {{kQ} \over R} = 9{{kq} \over r} = 9 \times 22$$ V
= 198 V
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