JEE MAIN - Physics (2022 - 25th June Evening Shift - No. 18)
If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be:
$${{KS} \over {(S + G)}}$$
$${{(G + S)} \over {nKS}}$$
$${{nKS} \over {(G + S)}}$$
$${{nK(G + S)} \over S}$$
Explanation
According to the information, current through galvanometer = nK
_25th_June_Evening_Shift_en_18_1.png)
$$ \Rightarrow {S \over {S + G}}i = nK$$
$$ \Rightarrow i = {{nK(S + G)} \over S}$$
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