JEE MAIN - Physics (2022 - 25th July Morning Shift - No. 7)
A certain amount of gas of volume $$\mathrm{V}$$ at $$27^{\circ} \mathrm{C}$$ temperature and pressure $$2 \times 10^{7} \mathrm{Nm}^{-2}$$ expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use $$\gamma=1.5)$$ :
$$3.536 \times 10^{5} \mathrm{~Pa}$$
$$3.536 \times 10^{6} \mathrm{~Pa}$$
$$1.25 \times 10^{6} \mathrm{~Pa}$$
$$1.25 \times 10^{5} \mathrm{~Pa}$$
Explanation
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Let AB is isothermal process and BC is adiabatic process then for AB process
PAVA = PBVB
$$\Rightarrow$$ PB = 107 Nm$$-$$2
For process BC
PBV$$_B^r$$ = PC V$$_C^r$$
PC = 3.536 x $$\times$$ 106 Pa
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