JEE MAIN - Physics (2022 - 25th July Morning Shift - No. 22)
Four forces are acting at a point $$\mathrm{P}$$ in equilibrium as shown in figure. The ratio of force $$\mathrm{F}_{1}$$ to $$\mathrm{F}_{2}$$ is $$1: x$$ where $$x=$$ _____________.
_25th_July_Morning_Shift_en_22_1.png)
Answer
3
Explanation
$${F_1} = \, + 2 \times {1 \over {\sqrt 2 }} - {1 \over {\sqrt 2 }} = {1 \over {\sqrt 2 }}$$
$${F_2} = 2 \times {1 \over {\sqrt 2 }} + {1 \over {\sqrt 2 }} = {3 \over {\sqrt 2 }}$$
_25th_July_Morning_Shift_en_22_2.png)
$${{{F_1}} \over {{F_2}}} = {1 \over 3} = {1 \over x} \Rightarrow x = 3$$
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