JEE MAIN - Physics (2022 - 25th July Morning Shift - No. 21)
A car is moving with speed of $$150 \mathrm{~km} / \mathrm{h}$$ and after applying the break it will move $$27 \mathrm{~m}$$ before it stops. If the same car is moving with a speed of one third the reported speed then it will stop after travelling ___________ m distance.
Answer
3
Explanation
$${F_R}\,d = {1 \over 2}m{v^2}$$
$${{{d_2}} \over {{d_1}}} = {\left( {{{{v_2}} \over {{v_1}}}} \right)^2} = {\left( {{1 \over 3}} \right)^2}$$
$${d_2} = {d_1} \times {1 \over 9} = 3m$$
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