JEE MAIN - Physics (2022 - 25th July Morning Shift - No. 18)
The momentum of an electron revolving in $$\mathrm{n}^{\text {th }}$$ orbit is given by :
(Symbols have their usual meanings)
$$\frac{\mathrm{nh}}{2 \pi \mathrm{r}}$$
$$
\frac{n h}{2 r}
$$
$$
\frac{\mathrm{nh}}{2 \pi}
$$
$$\frac{2 \pi r}{\mathrm{nh}}$$
Explanation
$$\because$$ $$mvr = {{nh} \over {2\pi }}$$
$$ \Rightarrow mv = {{nh} \over {2\pi r}}$$
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