JEE MAIN - Physics (2022 - 25th July Morning Shift - No. 14)
The rms value of conduction current in a parallel plate capacitor is $$6.9 \,\mu \mathrm{A}$$. The capacity of this capacitor, if it is connected to $$230 \mathrm{~V}$$ ac supply with an angular frequency of $$600 \,\mathrm{rad} / \mathrm{s}$$, will be :
5 pF
50 pF
100 pF
200 pF
Explanation
$${Z_C} = {V \over I}$$
$$ \Rightarrow {1 \over {\omega C}} = {{230} \over {6.9}}\,M\,\Omega $$
$$ \Rightarrow C = {{6.9} \over {230\,\omega }}\,\mu F$$
$$ = {{6.9} \over {230 \times 600}}\,\mu F$$
$$C = 50\,pF$$
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