JEE MAIN - Physics (2022 - 25th July Evening Shift - No. 8)
Light wave travelling in air along x-direction is given by $${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$$. Then, the peak value of magnetic field of wave will be (Given c = 3 $$\times$$ 108 ms$$-$$1)
18 $$\times$$ 10$$-$$7 T
54 $$\times$$ 10$$-$$7 T
54 $$\times$$ 10$$-$$8 T
18 $$\times$$ 10$$-$$8 T
Explanation
$$c = 3 \times {10^8}$$ m/sec
$$B = {E \over c} = {{540} \over {3 \times {{10}^8}}} = 18 \times {10^{ - 7}}\,T$$
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