JEE MAIN - Physics (2022 - 25th July Evening Shift - No. 19)
Three identical spheres each of mass M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 3 m each. Taking point of intersection of mutually perpendicular sides as origin, the magnitude of position vector of centre of mass of the system will be $$\sqrt x$$ m. The value of x is ____________.
Answer
2
Explanation
_25th_July_Evening_Shift_en_19_1.png)
$${d_{cm}} = 3\sin 45^\circ = {3 \over {\sqrt 2 }}$$
$${d_{cm}} = {2 \over 3} \times {3 \over {\sqrt 2 }} = \sqrt 2 = \sqrt x $$
$$x = 2$$
Comments (0)
