JEE MAIN - Physics (2022 - 25th July Evening Shift - No. 18)
A particle is moving in a straight line such that its velocity is increasing at 5 ms$$-$$1 per meter. The acceleration of the particle is _____________ ms$$-$$2 at a point where its velocity is 20 ms$$-$$1.
Answer
100
Explanation
$${{dv} \over {dx}} = 5$$ ms$$-$$1/m
Acceleration of particle
when $$v = 20$$ m/s
$$a = v{{dv} \over {dx}} = 20(5)$$ m/s2 = 100 m/s2
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