JEE MAIN - Physics (2022 - 25th July Evening Shift - No. 14)
A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms$$-$$1 gets embedded in it, then loss of kinetic energy will be :
4.9 J
9.8 J
14.7 J
19.6 J
Explanation
Loss in $$KE = {1 \over 2} \times {{{m_1}{m_2}} \over {{m_1} + {m_2}}} \times {v^2}$$
$$ = {1 \over 2} \times {{9.8 \times 0.2} \over {10}} \times {(10)^2}$$
$$= 9.8$$ J
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