JEE MAIN - Physics (2022 - 25th July Evening Shift - No. 10)
A current of 15 mA flows in the circuit as shown in figure. The value of potential difference between the points A and B will be:
_25th_July_Evening_Shift_en_10_1.png)
50 V
75 V
150 V
275 V
Explanation
Effective $$R = \left[ {5 + {{5 \times 10} \over {5 + 10}} + 10} \right]\,k\Omega $$
$$ = {{275} \over {15}}k\Omega $$
$$ \Rightarrow \Delta {V_{AB}} = 15\,mA \times {{275} \over {15}}k\Omega $$
$$ = 275$$ V
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