JEE MAIN - Physics (2022 - 24th June Morning Shift - No. 3)
Two identical cells each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20 $$\Omega$$. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is :
2.5 $$\Omega$$
4 $$\Omega$$
5 $$\Omega$$
10 $$\Omega$$
Explanation
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$${{1.5 \times 10} \over {10 + {r \over 2}}} = 1.2$$
$$\Rightarrow$$ r = 5 $$\Omega$$
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