JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 4)
Two identical charged particles each having a mass 10 g and charge 2.0 $$\times$$ 10$$-$$7C are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is 0.25, find the value of L. [Use g = 10 ms$$-$$2]
12 cm
10 cm
8 cm
5 cm
Explanation
According to given information:
$${{k{Q^2}} \over {{L^2}}}$$ = $$\mu$$mg
Putting the values, we get
L = 12 cm
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