JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 24)
A circular coil of 1000 turns each with area 1m2 is rotated about its vertical diameter at the rate of one revolution per second in a uniform horizontal magnetic field of 0.07T. The maximum voltage generation will be ___________ V.
Answer
440
Explanation
$${V_{\max }} = NAB\omega $$
$$ = 1000 \times 1 \times 0.07 \times (2\pi \times 1)$$
$$ \simeq 440$$ volts
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