JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 22)
In the given circuit, the value of current IL will be ____________ mA. (When RL = 1k$$\Omega$$)
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Answer
5
Explanation
VL = 5 V as VZ = 5 V
$$\therefore$$ $${I_L} = {{{V_L}} \over {{R_L}}} = {5 \over {{{10}^3}}} = 5$$ mA
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