JEE MAIN - Physics (2022 - 24th June Evening Shift - No. 21)
Two travelling waves of equal amplitudes and equal frequencies move in opposite directions along a string. They interfere to produce a stationary wave whose equation is given by $$y = (10\cos \pi x\sin {{2\pi t} \over T})$$ cm
The amplitude of the particle at $$x = {4 \over 3}$$ cm will be ___________ cm.
Answer
5
Explanation
$$A = \left| {10\cos (\pi x)} \right|$$
At $$x = {4 \over 3}$$
$$A = \left| {10\cos \left( {\pi \times {4 \over 3}} \right)} \right|$$
$$ = $$ | $$-$$ 5 cm |
$$\therefore$$ Amp = 5 cm
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